#linear-discounting

Question 1: Single choice

Two smoothing methods take probability mass from seen words: absolute discounting subtracts a constant $\delta$ from every non-zero count, and linear discounting multiplies every seen word's probability by $1 - \alpha$ . How much probability does a word seen $r$ times (out of $N$ ) lose?

$\delta / N$ under absolute and $\alpha r / N$ under linear discounting1
$\alpha r / N$ under absolute and $\delta / N$ under linear discounting2
The same amount $\delta / N$ under both methods3
Nothing; both only add probability to unseen words4

Timed test