#contrast

A $4 \times 4$ image with 3-bit gray levels ($L = 8$ levels, 0 to 7) is $\begin{bmatrix}2&3&3&4\\3&2&4&5\\4&3&6&3\\2&4&5&6\end{bmatrix}$. Histogram equalization maps level $v$ to $h(v) = \operatorname{round}\left(\frac{\operatorname{cdf}(v) - \operatorname{cdf}_{\min}}{N - \operatorname{cdf}_{\min}}(L - 1)\right)$, where $\operatorname{cdf}(v)$ counts the pixels with level $\le v$, $\operatorname{cdf}_{\min}$ is its smallest nonzero value and $N$ is the number of pixels. What is $h(4)$?